CHAPTER :- WORK,POWER,ENERGY
(SECTION-A)
1. A body of mass m is moving in a circle of radius r with a constant speed v.
The force on the body is
and is directed
towards the centre. What is the work done by this force in moving the body over
half the circumference of the circle
(A)
(B) Zero
(C)
(D) ![]()
2. A force acts on a 30 gm particle in such a way that the position of the particle as a
function of time is given by
, where x is
in metres and t is in seconds. The work done during the first 4 seconds is
(A) 5.28
J (B) 450 Mj
(C) 490
mJ (D) 530 mJ
3. A
particle is dropped from a height h. A constant horizontal velocity is given to
the particle. Taking g to be constant every where, kinetic energy E of the
particle with respect to time t is correctly shown in
(A)
(B)
(C)
(D) 
4. A force
acting on a
particle causes a displacement:
in its own
direction. If the work done is
then the value
of
is
(A)
0 (B) 1 (C) 6 (D)
12
5. A particle is acted upon by a force of constant
magnitude which is always perpendicular to the velocity of the particle, the
motion of the particle takes place in a plane. It follows that
(A) Its velocity is constant
(B)
Its acceleration is constant
(C)
Its kinetic energy is constant
(D)
It moves in a straight line
6. A particle moves under the effect of a force F
= Cx from x = 0 to
. The work done in the process is
(A)
(B)
(C)
(D) Zero
7. The potential energy of a certain spring when stretched through a
distance ‘S’ is 10 joule. The amount of work (in joule)
that must be done on this spring to stretch it through an additional distance ‘S’ will be
(A) 30 (B)
40 (C) 10 (D) 20
8. The spring extends by x on loading, then energy stored by the spring is :
(if
T is the tension in spring and k is spring constant)
(A)
(B)
(C)
(D) ![]()
9. The potential energy between two atoms in a
molecule is given by
; where a
and b are positive constants and x is the distance between the atoms. The
atom is in stable equilibrium when
(A)
(B)
![]()
(C)
(D) ![]()
10. A light and a heavy body have equal momenta.
Which one has greater K.E
(A) The light body
(B) The heavy body
(C) The K.E. are equal
(D) Data is incomplete
11. A body of mass 2 kg is thrown up vertically with K.E. of 490 joules. If the
acceleration due to gravity is 9.8
, then the height at which the K.E. of the body
becomes half its original value is given by
(A) 50 m (B) 12.5 m
(C) 25 m (D)
10 m
12. If the K.E.
of a body is increased by 300%, its momentum will increase by
(A) 100% (B)
150%
(C)
(D) 175%
13. A light and a heavy body have equal kinetic energy. Which one has a
greater momentum ?
(A) The
light body
(B) The
heavy body
(C)
Both have equal momentum
(D) It is not possible to say
anything without additional information
14. A 4 kg mass and a 1 kg mass are moving with equal kinetic
energies. The ratio of the magnitudes of their linear momenta is
(A) 1 :
2 (B)
1 : 1
(C) 2 :
1 (D) 4 : 1
15. A block of mass m is attached to two
unstretched springs of spring constants k1 and k2 as shown in figure. The block is displaced
towards right through a distance x and is released. Find the speed of the block
as it passes through the mean position shown.

(A)
(B)
(C)
(D) ![]()
16. What is the velocity of the bob of a simple
pendulum at its mean position, if it is able to rise to vertical height of
(Take ![]()

(A)
0.6 m/s (B)
1.4 m/s
(C)
1.8 m/s (D)
2.2 m/s
17. A bomb of mass 9kg explodes into 2 pieces of mass 3kg and 6kg. The velocity
of mass 3kg is 1.6 m/s,
the K.E. of mass 6kg is.
(A) 3.84 J (B) 9.6 J
(C) 1.92 J (D) 2.92 J
18. A bomb of mass 3.0 Kg explodes in air into two pieces of masses 2.0 kg and 1.0 kg. The smaller mass goes at a speed of 80 m/s.The total energy imparted to the two fragments is.
(A) 1.07 kJ (B) 2.14 kJ
(C) 2.4 kJ (D) 4.8 kJ
19. A block of mass m initially at rest is dropped from a height h on to a spring of force constant k. the maximum compression in the spring is x then.

(A)
(B)
(C)
(D) ![]()
20. A body of mass m accelerates uniformly from rest to
in time
. As a function of time t, the instantaneous power delivered to the body is.
(A)
(B)
(C)
(D) ![]()
21. A weight lifter lifts 300 kg from the ground to a height of 2 meter in 3 second. The average power generated by him is
(A) 5880
watt (B)
4410 watt
(C) 2205
watt (D)
1960 watt
22. A 60 kg
man runs up a staircase in 12 seconds while a 50 kg man runs up the same staircase in 11, seconds, the ratio of the
rate of doing their work is
(A) 6 : 5 (B) 12 : 11
(C)
11 : 10 (D)
10 : 11
23. A force of
acts on a body for 4 second, produces a displacement
of
The power used is
(A) 9.5 W (B) 7.5 W
(C) 6.5 W (D) 4.5 W
24. A wedge of mass M fitted with a spring
of stiffness ‘k’ is kept on a smooth horizontal surface. A rod of mass m is
kept on the wedge as shown in the figure. System is in equilibrium. Assuming
that all surfaces are smooth, the potential energy stored in the spring is :

(A)
(B)
(C)
(D) ![]()
25. A car of mass ‘m’
is driven with acceleration ‘a’ along a straight level road against a constant
external resistive force ‘R’. When the velocity of the car is ‘V’, the rate at which the engine of the car is doing
work will be
(A) RV (B) maV
(C) (R + ma)V (D) (ma – R)V
26. A particle of mass m moving with horizontal speed 6 m/sec as shown in figure.
If
then for one
dimensional elastic collision, the speed of lighter particle after collision
will be
![]()
(A) 2m/sec in original direction
(B) 2 m/sec opposite to the
original direction
(C) 4 m/sec opposite to the
original direction
(D) 4 m/sec in original
direction
27. A steel ball of radius 2 cm is at rest on a frictionless surface. Another ball of radius 4cm moving at a velocity of 81 cm/sec
collides elastically with first ball. After collision the smaller ball moves
with speed of
(A)
81 cm/sec (B) 63 cm/sec
(C)
144 cm/sec (D) None of
these
28. A particle moves under the influence of
a force F = kx in one dimensions (k is a positive constant and x is the
distance of the particle from the origin). Assume that the potential energy of
the particle at the origin is zero, the schematic diagram of the potential
energy U as a function of x is given by
(A)
(B) 
(C)
(D) 
29. Which of the following statements is true
(A) In
elastic collisions, the momentum is conserved but not in inelastic collisions
(B) Both
kinetic energy and momentum are conserved in elastic as well as inelastic collisions
(C) Total kinetic energy is not conserved but momentum is
conserved in inelastic collisions
(D) Total
kinetic energy is conserved in elastic collisions but momentum is not conserved
in elastic collisions
30. A mass 'm' moves with a velocity 'v'
and collides inelastically with another identical mass. After collision the Ist
mass moves with velocity
in a direction
perpendicular to the initial direction of motion. Find the speed of the 2nd
mass after collision

(A)
(B)
(C) v (D) ![]()
31. A bullet hits and gets embedded in a solid block resting on a horizontal
frictionless table. What is conserved ?
(A) Momentum and kinetic energy
(B) Kinetic energy alone
(C) Momentum alone
(D) Neither momentum nor kinetic
energy
32. A moving body of mass m and
velocity 3 km/h collides with a rest body of mass 2m and sticks to it. Now the combined mass starts to move. What will
be the combined velocity
(A) 3 km/h (B) 2 km/h
(C) 1 km/h (D) 4 km/h
33. A metal ball of mass 2 kg
moving with a velocity of 36 km/h has an head on collision with a
stationary ball of mass 3 kg. If
after the collision, the two balls move together, the loss in kinetic energy
due to collision is
(A) 40 J (B) 60 J
(C) 100 J (D) 140 J
34. A force-time graph for a linear motion is shown in figure where the
segments are circular. The linear momentum gained between zero and 8 second is

(A)
(B) ![]()
(C)
(D) ![]()
35. Figure shows the F-x graph. Where F is the force applied and x is the distance covered
by
the body along a straight line path. Given that F is in newton and x in metre,
what is the work done ?
(A)
10 J (B) 20 J
(C)
30 J (D) 40 J
(SECTION-B)
36. Assertion : The rate of change of total
momentum of a many particle system is proportional to the sum of the internal
forces of the system.
Reason : Internal forces can change
the kinetic energy but not the momentum of the system.
(A)
If both assertion and reason are true and the reason is the correct explanation
of the assertion.
(B)
If both assertion and reason are true but reason is not the correct explanation
of the assertion.
(C)
If assertion is true but reason is false.
(D)
Both assertion and reason are false
37. A body of mass 6kg is under a force which causes displacement in it given by
metres where t is time. The work done by the force in 2 seconds is
(A) 12 J (B) 9 J
(C) 6 J (D) 3 J
38. If W1, W2 and W3 represent the work done in
moving a particle from A to B along three different paths 1, 2, 3 respectively
(as shown) in the gravitational field of a point mass m, find the correct
relation between W1, W2 and W3

(A) W1 > W2 > W3
(B) W1 = W2 = W3
(C) W1 < W2 < W3
(D) W2 > W1 > W3
39. A uniform chain of length 2m is kept on a table such that a length
of 60cm hangs freely from the edge of
the table. The total mass of the chain is 4kg.
What is the work done in pulling the entire chain on the table
(A) 7.2 J (B) 3.6 J
(C) 120 J (D) 1200 J
40. An engine pumps water through a hose pipe.
Water passes through the pipe and leaves it with a velocity of 2 m/s. The mass
per unit length of water in the pipe is 100 kg/m. What is the power of the
engine?
(A) 400 W (B) 200 W
(C) 100 W (D) 800 W
41. The force constant of a wire is k and that of another wire is
When both the
wires are stretched through same distance, then the work done
(A)
(B)
![]()
(C)
(D) ![]()
42. A mass of 0.5kg moving with a speed of 1.5 m/s
on a horizontal smooth surface, collides with a nearly weightless spring of
force constant
. The maximum compression of the spring would be
(A) 0.15 m (B) 0.12 m
(C) 1.5 m (D) 0.5 m
43. A car of mass m starts from rest and
accelerates so that the instantaneous power delivered to the car has a constant
magnitude P0. The instantaneous velocity of this car
is proportional to :
(A) t2P0 (B) t1/2
(C) t–1/2 (D) ![]()
44. Power of a water pump is 2 kW. If
, the amount of water it can raise in one minute to a
height of 10 m is
(A) 2000
litre (B)
1000 litre
(C) 100
litre (D)
1200 litre
45. How much work does a pulling force of 40 N do on the 20 kg box in pulling it 8 m
across the floor at a constant speed. The pulling force is directed at 60°
above the horizontal
(A) 160
J
(B) 277 J
(C) 784
J
(D) None of the above
46. Work done in time t on a body of mass m
which is accelerated from rest to a speed v
in time
as a function
of time t is given by
(A)
(B)
![]()
(C)
(D)
![]()
47. The slope of kinetic energy displacement
curve of a particle in motion is
(A) Equal
to the acceleration of the particle
(B) Inversely
proportional to the acceleration
(C) Directly
proportional to the acceleration
(D) None
of the above
48. The energy required to accelerate a car from 10 m/s to 20 m/s
is how many times the energy required to accelerate the car from rest to 10 m/s
(A) Equal (B) 4
times
(C) 2 times (D)
3 times
49. A body of mass 2 kg slides down
a curved track which is quadrant of a circle of radius 1 metre. All the surfaces are frictionless. If the body starts from
rest, its speed at the bottom of the track is

(A) 4.43 m/sec (B) 2 m/sec
(C) 0.5 m/sec (D) 19.6 m/sec
50. Match the column I with column II.
Column I
(i) When a
body does work against friction, its kinetic energy
(ii) Work done by a body is
(iii) Power of a body varies
inversely as
(iv) When work done over a closed
path is zero
Column II
(p)
independent of time
(q)
time
(r)
force must be conservative
(s) decreases
(A) i-p,ii-q, iii-r,iv-s
(B) i-q,ii-r, iii-s,iv-p
(C) i-s,ii-r, iii-q,iv-p
(D) i-s,ii-p, iii-q,iv-r
CHAPTER
:- WORK,POWER,ENERGY
ANSWER KEY
1. (B) 2. (A) 3. (A) 4. (C) 5. (C) 6. (B) 7. (A)
8. (A) 9. (D) 10. (A) 11. (B) 12. (A) 13. (B) 14. (C)
15. (A) 16. (B) 17. (C) 18. (D) 19. (B) 20. (D) 21. (D)
22. (C) 23. (A) 24. (C) 25. (C) 26. (A) 27. (C) 28. (A)
29. (C) 30. (A) 31. (C) 32. (C) 33. (B) 34. (B) 35. (A)
36. (D) 37. (D) 38. (B) 39. (B) 40. (A) 41. (B) 42. (A)
43. (B) 44. (D) 45. (A) 46. (D) 47. (C) 48. (D) 49. (A)
50. (D)
SOLUTIONS
SECTION-A
1. (B)
Sol. Work done by centripetal force is always zero, because force and instantaneous displacement are always perpendicular.
![]()
2. (A)
Sol. ![]()
\
and ![]()
(According to
work energy theorem)
![]()
3. (A)
Sol. h =
gt2, W = mgh = mg
, W = Kf – Ki
= Kf –
mu2, Kf =
mu2 + ![]()
Hence Ans. is
(A)
4. (C)
Sol. ![]()
Þ ![]()
5. (C)
Sol. When a force of constant magnitude which is perpendicular to the velocity
of particle acts on a particle, work done is zero and hence change in kinetic
energy is zero.
6. (B)
Sol. ![]()
7. (A)
Sol.
(given
in the problem)
=
3 × 10 = 30 J
8. (A)
Sol. ![]()
9. (D)
Sol. Condition for stable equilibrium ![]()
Þ
Þ ![]()
Þ
Þ
Þ ![]()
10. (A)
Sol.
if P = constant then![]()
11. (B)
Sol. Let h
is that height at which the kinetic energy of the body becomes half its
original value i.e. half of its
kinetic energy will convert into potential energy
\ mgh =
Þ
Þ ![]()
12. (A)
Sol. Let initial kinetic energy,
Final kinetic energy,
of E = 4E
As
Þ
Þ ![]()
Þ
of ![]()
i.e. Momentum will increase by 100%
13. (B)
Sol.
if E are equal then
i.e. heavier body will
possess greater momentum.
14. (C)
Sol.
If E are const. then
= 2
15. (A)
Sol.
K2 x2 +
K1x2 =
m v2
v
= ![]()
16. (B)
Sol. ![]()
17. (C)
Sol.

As the bomb initially
was at rest therefore
Initial momentum of bomb = 0
Final momentum of system = ![]()
As there is no external force
\
Þ ![]()
velocity of 6 kg
mass
(numerically)
![]()
![]()
18. (D)
Sol. Both fragment will possess the equal linear momentum
Þ
Þ
\ Total energy of system![]()
= ![]()
= 4800 J = 4.8 kJ
19. (B)
Sol. Change in gravitational potential energy
= Elastic potential
energy stored in compressed spring
![]()
20. (D)
Sol. ![]()
![]()
[as u = 0]
![]()
![]()
21. (D)
Sol. P
=
![]()
![]()
22. (C)
Sol.
Þ
(As h =
constant)
\![]()
23. (A)
Sol. ![]()
![]()
24. (C)
Sol. For
m, N cos q = mg
For
M , N sin q = kx
So
tan q = ![]()
so
Kx2 =
25. (C)
Sol. F – R = ma, F = R + ma,
P = Fv = (R + ma)v
26. (A)
Sol.

![]()
Substituting m1 = 0, ![]()
Þ
![]()
i.e. the
lighter particle will move in original direction
with the speed of 2 m/s.
27. (C)
Sol. Ratio in radius of steel balls = 1/2
So, ratio in their masses
[As
]
Let
and ![]()
![]()
![]()
28. (A)
Sol. From F =

\ U(x) = ![]()
as
U(0) = 0
Therefore, the correct option is
(A).
29. (C)
30. (A)
Sol. Let mass A moves with
velocity v and collides inelastically
with mass B, which is at rest.

According to problem mass A moves in a perpendicular direction and
let the mass B moves at angle q with the horizontal with velocity v.
Initial
horizontal momentum of system
(beforecollision)=mv
....(i)
Final
horizontal momentum of system
(after
collision) = Mv cosq ...(ii)
From
the conservation of horizontal linear momentum mv
= mV cosq Þ v = V cosq
...(iii)
Initial
vertical momentum of system (before collision) is zero.
Final
vertical momentum of system ![]()
From
the conservation of vertical linear momentum ![]()
Þ
...(iv)
By
solving (iii) and (iv)
Þ
Þ
.
31. (C)
32. (C)
Sol.

Initial momentum = ![]()
Final momentum = ![]()
By the law of conservation of momentum
Þ ![]()
33. (B)
Sol. ![]()
By law of conservation of momentum
Þ ![]()
Loss in K.E.![]()
34. (B)
Sol. Here
\ K.E.![]()
![]()
Total energy ![]()
35. (A)
Sol. Work done = area under
curve and displacement axis
=
SECTION-B
36. (D)
Sol. Rate of change of momentum is proportional to
external forces acting on the system. The total momentum of whole system remain
constant when no external force is acted upon it.
Internal forces can
change the kinetic energy of the system.
37. (D)
Sol. (D)
\![]()
![]()
Now ![]()
38. (B)
Sol. Gravitational force is
conservative
so W1 = W2 = W3
39. (B)
Sol. Fraction of length of the chain hanging from the table
Þ ![]()
Work done in pulling the
chain on the table
![]()
![]()

40. (A)
Sol. Here ,
Mass
per unit length of water, m
= 100 kg/m
Velocity
of water, v = 2m/s
Power
of engine, P =
= 400W
41. (B)
Sol.
If both wires are
stretched through same distance then
. As
so ![]()
42. (A)
Sol. The kinetic energy of mass is converted into potential energy of a spring
![]()
Þ ![]()
43. (B)
Sol. Constant
power of car P0 = F.V. = ma.v
P0 = ![]()
P0 dt = mvdv
P0.t = ![]()
v
=
![]()
44. (D)
Sol. P =
Þ m = ![]()
kg
As volume = ![]()
Þ ![]()
Volume = ![]()
45. (A)
Sol. ![]()
46. (D)
Sol. Work done =
![]()
\W=![]()
![]()
47. (C)
Sol.
Differentiating
w.r.t. x, we get
![]()
48. (D)
Sol. Kinetic energy for first
condition
=
= ![]()
K.E. for second condition = ![]()
\ ![]()
49. (A)
Sol. By conservation of energy, ![]()
Þ ![]()
50. (D)
Sol. When a body does work against friction, its kinetic
energy its kinetic energy is decreases.
Work done by a body is dependent of time
Power of a body varies inversely as time
When work done over a closed path is zero force must be
conservative.
Thus option D is correct.
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